epsilon-delta proofs 7

Let random variables$X_1,X_2,\cdots,X_n$ be i.i.d. and any $E(X_i)=\mu<\infty$. If we put
$$Y_n=\frac{1}{n}\sum_{i=1}^nX_i$$
then law of large numbers says,
$$P(\lim_{n\rightarrow\infty}Y_n=\mu)=1$$
It means, for any $\epsilon>0$ there is a $N$ such that if $n>N$, $|Y_n-\mu|\leq \epsilon$ and it's probability becomes 1.

In the probability theory, as we are used to write elements $w$ of the sample space explicitly,
$$P (w |\lim_{n\rightarrow\infty}Y_n(w)=\mu )=1.$$
Therefore, when $1/j,(j\in \mathbb{N})$  is used in place of $\epsilon$, if a set $A$ is defined by
$$A=\left\{w |\forall j, \exists N, n\geq N, |Y_n-\mu|<1/j \right\}$$
, then $P(A)=1$  .  Furthermore, using symbols of the set theory, if a set $A$ is
$$A=\bigcap_{j=1}^{\infty}\bigcup_{N=1}^{\infty}\bigcap_{n=N}^{\infty}  \left\{w  |  |Y_n-\mu|<1/j \right\}$$
, then $P(A)=1$  .

A epsilon-delta technique can be written in the form like this.