Supposed that a set $C$ , and a set $J$ which fully covers $C$ .
$C\subset J$
The set $C$ is arbitrary. Its shape may be complicated, or not .
However $J$ is measurable.
For example, $J$ is a big square, and $m(J)$ is height multiplied by width.
$m(C)\leq m(J)$
If a set is measurable, the value of the measure is equal to it of the outer measure.
$m(J)=m^o(J)=|J|$
Then, an inner measure $m^i$ will be defined by the outer measure,
\[ m^i(C)=|J|-m^o(J\cap C^c) . \]
, where $C^c$ is the complementary set of $C$ .
We must accept that there exist some measurable sets $J$ which fully cover an aribtrary set $C$ .
It would not be strong opposition.
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