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2017/09/30

classical logics (an addition)

You must know that A\subset A is always true.
Thus, although an proposition A is false,  A\subset A is true.

With similar, if an proposition A is false, then
A\sim A is true.

However, as an proposition A is false,
A\cdot A is false, and
A\vee A is false.

Please check the truth of the proposition "A\subset (B\vee C) ",
where A is false, B is false, and C is false.

If A is "a day has 25 hours ",
B is "a week has 175(=25×7) hours " and
C is "a month has 750(=25×30) hours" , then
"A\subset (B\vee C) " is true .

How do you feel it?









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